# Line slope calculator 5x-3y=6

**Straight line given by points A[3; 3] and B[6; 8]**

## Calculation:

**Slope-intercept form of line:**y = 1.6667x-2

**Canonical form of the line equation:**5x-3y-6 = 0

**Parametric form of the line equation:**

x = 3t+3

y = 5t+3 ; t ∈ R

**Slope:**m = 1.6667

**Slope angle of line: φ =**59°2'10″ = 1.0304 rad

**X intercept:**x

_{0}= 1.2

**Y intercept:**y

_{0}= q = -2

**Distance line from the origin:**d

_{0}= 1.029

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; 5)

**Normal vector: n =**(5; -3)

**Midpoint of the segment AB: M =**[4.5; 5.5]

**Perpendicular Bisector equation:**3x+5y-41 = 0

**Vector OA = (3; 3) ; |OA| = 4.2426**

**Vector OB = (6; 8) ; |OB| = 10**

**Scalar product OA .OB = 42**

**Angle ∠ AOB = 8°7'48″ = 0.1419 rad**